Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsGauss LawMedium2 minQB
PhysicsMediummultiple choice

Graph shows the variation of potential (V), magnitude of electric field (E), charge enclosed within the concentric sphere and net flux through a concentric spherical Gaussian surface as a function of distance ( r ) from centre of a uniformly positive charged solid sphere of radius R . Choose the CORRECT option(s).

Options:(select one or more)

Answer:
A, B, C
Solution:

For a uniformly charged solid sphere, falls as inside and as outside - (A) correct.

rises linearly up to and falls as outside - (B) correct.

grows as up to and stays constant beyond - (C) correct.

Net flux equals , so it must saturate, not peak and decay - (D) wrong.

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Gauss Law
⏱ 2mℹ️ Source: QB

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