In a cuboid of dimension 2 L × 2 L × L , a charge q is placed at the centre of the surface ' S ' having area of 4 L 2 . The flux through the opposite surface to ' S ' is given by

Question

TestHub · Accepted Answer

After placing similar cubic at the bottom, we get cube of side $2 L$ having change $q$ at its centre.

From the Gauss's law electric flux through whole

Flux passing through shaded face
$ϕ = \frac{q / ε _{0}}{6} = \frac{q}{6 ε _{0}}$

Physics - Electrostatics Question with Solution | TestHub

Options:

Doubts & Discussion