Physics - Electrostatics Question with Solution | TestHub

Let thenumber of $\alpha$ and $\beta$ particles emitted be $\mathrm{m}$ and $\mathrm{n}$ respectively. Then $\mathrm{A}-4\mathrm{m}=\mathrm{A}-8\Rightarrow \mathrm{m}=2$ $[\because$ the mass number of a radioactive nuclide decreases by 4 due to emission of one $\alpha$ particle] Again, $(Z-2m)+n=Z-3$ $[\because$ the atomic number decreases by 2 due to emission of $1\alpha$-particle but increases by 1 due to emission of $1\beta$-particle] or $-2\mathrm{m}+\mathrm{n}=-3$ or $2\mathrm{m}-\mathrm{n}=3$ or $(2\times 2)-\mathrm{n}=3(\because \mathrm{m}=2)$ $\Rightarrow \mathrm{n}=1$