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Physics - Elasticity Question with Solution | TestHub

PhysicsElasticityMiscellaneousEasy2 minQB

PhysicsEasysingle choice

A steel wire ( $Y = 200 GPa$ ) of cross-sectional area $1 mm^{2}$ and length $2 m$ is stretched by a force of $1000 N$ . The elastic potential energy stored in the wire is :

Options:

Answer:

Solution:

Energy $= \frac{1}{2} (stress) (strain) \times volume$

Stress $= \frac{1000}{1 \times 1 0 ^{- 6}} = 1 0^{9} N/ m^{2}$ , strain $= \frac{1 0 ^{9}}{200 \times 1 0 ^{9}} = 5 \times 1 0^{- 3}$

Volume $= 1 0^{- 6} \times 2 = 2 \times 1 0^{- 6} m^{3}$

Energy $= \frac{1}{2} \times 1 0^{9} \times 5 \times 1 0^{- 3} \times 2 \times 1 0^{- 6} = 5 J$

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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