The bulk modulus of a liquid is 3 × 10 10 Nm - 2 . The pressure required to reduce the volume of liquid by 2 % is :

Bulk modulus B = Volumetric stress Volumetric strain = - ∆ P ∆ V V Then, ∆ P = B × - ∆ V V = 3 × 10 10 × 2 100 = 6 × 10 8 N m - 2

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PhysicsElasticityMiscellaneousEasy2 minPYQ_2022

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The bulk modulus of a liquid is $3 \times 10^{10} {Nm}^{- 2}$ . The pressure required to reduce the volume of liquid by $2 %$ is :

Answer:

Solution:

Bulk modulus $B = \frac{Volumetric stress}{Volumetric strain} = \frac{- ∆ P}{\frac{∆ V}{V}}$

Then, $∆ P = B \times (- \frac{∆ V}{V}) = 3 \times 10^{10} \times \frac{2}{100} = 6 \times 10^{8} N m^{- 2}$

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2022

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