Physics - Elasticity Question with Solution | TestHub

A brass rod of length $L$ and cross section area $2{\mathrm{cm}}^2$ is attached end to end to a steel rod of length $2\mathrm{m}$ and cross sectional area $1{\mathrm{cm}}^2$. The compound rod is subjected to equal and opposite tensile force of magnitude $5\times 10^4\mathrm{N}$ at its ends. If the elongation of the two rods are equal. Then the length of brass rod is [$Y_{\text{brass}}=10^{11}N/{\mathrm{m}}^2$, $Y_{\text{steel}}=2\times 10^{11}N/{\mathrm{m}}^2$]