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Physics - Elasticity Question with Solution | TestHub

PhysicsElasticityMiscellaneousMedium2 minPYQ_2019

PhysicsMediumsingle choice

When a block of mass $M$ is suspended by a long wire of length $L$ , the length of the wire becomes $(L + l) .$ The elastic potential energy stored in the extended wire isNEET 2019 (All India)

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Answer:

Solution:

$\frac{1}{2} K {(l)}^{2} =$ energy
$K (l) = M g$
$K = \frac{M g}{l}$
$∴$ Energy $= \frac{1}{2} K l^{2} = \frac{1}{2} \frac{M g}{l} l^{2}$
$= \frac{M g l}{2}$

Stream:NEETSubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2019

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