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Physics - Elasticity Question with Solution | TestHub

PhysicsElasticityMiscellaneousEasy2 minQB

PhysicsEasysingle choice

A steel wire ( $Y = 200 GPa$ ) of cross-sectional area $1 mm^{2}$ is stretched by a force of $1000 N$ . The percentage increase in length of the wire is

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Answer:

Solution:

Percentage increase $= \frac{Δ ℓ}{ℓ} \times 100 = strain \times 100$

Strain $= \frac{stress}{Y} = \frac{1000/ ( 1 \times 1 0 ^{- 6} )}{200 \times 1 0 ^{9}} = 5 \times 1 0^{- 3}$

Percentage increase $= 0.5%$

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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