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PhysicsElasticityMiscellaneousMedium2 minQB

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A uniform rod of length $2 l$ , area $A$ , modulus $Y$ experiences the forces shown. Elongation is:

Answer:

Solution:

Left half tension is $F$ .

Right half tension is $2 F$ .

$Δ L = \frac{Fl}{A Y} + \frac{2 Fl}{A Y} = \frac{3 Fl}{A Y}$ .

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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