A heavy block suspended by an elastic spring of negligible mass produces an extension of 12 cm when it is in equilibrium. When a length of one fourth of the spring is cut off and the remaining three-f

Question

A heavy block suspended by an elastic spring of negligible mass produces an extension of 12 cm when it is in equilibrium. When a length of one fourth of the spring is cut off and the remaining three-fourths length is used to suspend the block the extension in cm, when the block is in equilibrium is

TestHub · Accepted Answer

M g = k 1 ​ x 1 ​ and M g = k 2 ​ x 2 ​ x 2 ​ = k 2 ​ k 1 ​ x 1 ​ ​ Spring constant is inversely proportional to length. For 4 3 ​ of the length, k 2 ​ = 3 4 ​ k and k 1 ​ = k . x 2 ​ = ( 4/3 ) k k × 12 ​ = 9 cm

Physics - Elasticity Question with Solution | TestHub

Options:

Doubts & Discussion