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PhysicsElasticityMiscellaneousMedium2 minPYQ_2022
PhysicsMediumsingle choice

A wire of lengthLis hanging from a fixed support. The length changes toL1andL2when masses1 kgand2 kgare suspended respectively from its free end. Then the value ofLis equal to

Options:

Answer:
C
Solution:

From Hooke's law, L=FLAYLF. Therefore,

L2-LL1-L=m2gm1g=21  L=2L1-L2

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous
2mℹ️ Source: PYQ_2022

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