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Physics - Elasticity Question with Solution | TestHub

PhysicsElasticityMiscellaneousMedium2 minPYQ_2022

PhysicsMediumsingle choice

A wire of length $L$ is hanging from a fixed support. The length changes to $L_{1}$ and $L_{2}$ when masses $1 kg$ and $2 kg$ are suspended respectively from its free end. Then the value of $L$ is equal to

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Answer:

Solution:

From Hooke's law, $∆ L = \frac{F L}{A Y} \Rightarrow ∆ L \propto F$ . Therefore,

$\frac{L_{2} - L}{L_{1} - L} = \frac{m_{2} g}{m_{1} g} = \frac{2}{1}$ $\Rightarrow L = 2 L_{1} - L_{2}$

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2022

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