In the ratio of diameters, lengths and Young's modulus of steel and copper wires shown in the figure are p , q and s respectively, then the corresponding ratio of increase in their length would b

Question

In the ratio of diameters, lengths and Young's modulus of steel and copper wires shown in the figure are p , q and s respectively, then the corresponding ratio of increase in their length would be:NEET 2013 (Karnataka)

TestHub · Accepted Answer

We know that Young’s modulus γ ⇒ Δ L ​ = Δ4 L FL ​ = π D 2 4 L 4 FL ​ = π D 2 L 4 FL ​ ​ According to questions. ​ Δ L C ​ Δ L S ​ ​ = F C ​ F S ​ ​ ⋅ L C ​ L S ​ ​ ⋅ D S 2 ​ L C ​ D C 2 ​ L S ​ ​ Here F S ​ = ( 5 m + 2 m ) g = 7 mg F C ​ = 5 mg , = ? , D C ​ D S ​ ​ = P , L C ​ L S ​ ​ = S ​ Putting in eq. (ii) Δ L C ​ Δ L S ​ ​ ​ = 5 mg 7 mg ​ × q + ( P 1 ​ ) 2 ( S 1 ​ ) = 5 p 2 S 7 q ​ ​

Physics - Elasticity Question with Solution | TestHub

Options:

Doubts & Discussion