Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical instrumentEasy2 minQB

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A galvanometer has a current range of $15 mA$ and a voltage range of $750 mV$ . To convert this galvanometer into an ammeter of range $25 A$ , the required shunt is

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Answer:

Solution:

$V = 750 \times 10^{- 3} V$

$I_{g} = 15 \times 10^{- 3} A$

and $I = 25 A$

Using the relation, $R = \frac{V}{I_{g}}$ , resistance of galvanometer is

$= \frac{750 \times 10^{- 3}}{15 \times 10^{- 3}}$

$= 50 Ω$

$I_{g} = \frac{S}{S + R} \times I$

$15 \times 10^{- 3} = (\frac{S}{S + 50}) \times 25$

$S = 0.03 Ω$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Electrical instrument

⏱ 2mℹ️ Source: QB

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