An electric bulb of 500 W at 100 V is used in a circuit having a 200 V supply. Calculate the resistance R to be connected in series with the bulb so that the power delivered by the bulb is 500 W .

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TestHub · Accepted Answer

Resistance of bulb P = V 2 r r = ( 100 ) 2 500 = 100 × 100 500 = 20 i = P V = 500 100 = 5 A Δ V in resistance R = 100 V R = 100 5 = 20 Ω

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