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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityEquivalent ResistanceHard2 minQB

PhysicsHardnumerical

Twelve wires each having resistance $2Ω$ are joined to form a cube. A battery of $6 V$ emf is joined across point $a$ and $c$ . The voltage difference between $e$ and $f$ is ______V.

Answer:

1.00

Solution:

From symmetry, current through e-b & g-d =0 $∴ R_{eq} = \frac{3}{4} \times R = \frac{3}{2} Ω ∴ Current through battery = \frac{6 \times 2}{3} = 4 A i_{2} = \frac{4}{8} \times 2 = 1 A ∴ Δ V across e-f = \frac{i _{2}}{2} \times R = \frac{1}{2} \times 2 = 1 V$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Equivalent Resistance

⏱ 2mℹ️ Source: QB

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