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PhysicsCurrent ElectricityElectrical PowerEasy2 minPYQ_2020

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Two heating coils of resistances $10 Ω$ and $20 Ω$ are connected in parallel and are connected to a battery of emf $12 V$ and internal resistance $1 Ω$ . The power consumed by them are in the ratio

Options:

Answer:

Solution:

Power, $P = i^{2} R = \frac{V^{2}}{R}$

$P_{1} = \frac{V^{2}}{R_{1}}$

$P_{2} = \frac{V^{2}}{R_{2}}$

$∴ \frac{P_{1}}{P_{2}} = \frac{R_{2}}{R_{1}} = \frac{20}{10} = \frac{2}{1} o r 2 : 1$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Electrical Power

⏱ 2mℹ️ Source: PYQ_2020

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