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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical PowerEasy2 minQB

PhysicsEasysingle choice

There are ' $n$ ' number of identical electric bulbs, each is designed to draw a power $p$ independently from the mains supply. They are now joined in series across the main supply. The total power drawn by the combination is :

Options:

Answer:

Solution:

$R_{s} = R_{1} + R_{2} + R_{3} + \dots\dots .. + R_{n} \frac{V ^{2}}{P _{s}} = \frac{V ^{2}}{P} + \frac{V ^{2}}{P} + \dots\dots . + \frac{V ^{2}}{P _{n}} P_{s} = \frac{P}{n}$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Electrical Power

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