Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical instrumentEasy2 minQB
PhysicsEasysingle choice

Two cells of E.M.F.E1andE2 E2 > E1are connected in series in the secondary circuit of a potentiometer experiment for determination of E.M.F. The balancing length is found to be825 cm. Now when the terminals of cellE1are reversed, then the balancing length is found to be225 cm. The ratio ofE1andE2is

Options:

Answer:
B
Solution:

E2 + E1 = x825

E2 – E1 = x225

Dividing above equations, we get

E2+E1E2-E1=113

Appling componendo and dividendo, we get

E1E2=47

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Electrical instrument
⏱ 2mℹ️ Source: QB

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