A galvanometer has a resistance of 50Ω . If a resistance of 1Ω is connected across its terminals, the total current flow through the galvanometer is [ I g represents the maximum current that can be

Question

A galvanometer has a resistance of 50Ω . If a resistance of 1Ω is connected across its terminals, the total current flow through the galvanometer is [ I g ​ represents the maximum current that can be passed through the galvanometer]

TestHub · Accepted Answer

In the galvanometer, I g ​ = max . current through galvanometer, S = shunt resistance, G = galvanometer resistance then I g ​ ( galvanometer ) = I ( G + S S ​ ) ⇒ I = I g ​ ( S G + S ​ ) = ( 1 50 + 1 ​ ) I g ​ = 51 I g ​ ​

Physics - Current Electricity Question with Solution | TestHub

Options:

Doubts & Discussion