The EMF of a battery is determined using the following circuit with wire AB. The galvanometer shows zero deflection when one of it's terminals is connected to point C. If the internal resistance of the battery is zero, then what is emf of battery (in volt)? Length of wire AB is 100 cm.

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Ans (3.75) Potential gradient along wire AB = 40 cm 1.5 volt ​ = 80 3 ​ V/cm So ( V A ​ − V B ​ ) = 80 3 ​ × 100 = 3.75 volt So emf of battery E = 3.75 Volt

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