A current of 2 mA was passed through an unknown resistor which dissipated a power of 4.4 W . Dissipated power when an ideal power supply of 11 V is connected across it is:

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P = V 2 R = i 2 R R e s i s t a n c e R = V 2 P = P i 2 Here, Power P = 4.4 W a n d i = 2 mA so R = 4.4 4 × 10 - 6 Ω When 11 V power supply is connected across R P ′ = 11 2 4.4 × 4 × 10 - 6 = 11 × 10 - 5 W .

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