Twelve wires each having resistance 2Ω are joined to form a cube. A battery of 6 V emf is joined across point a and c . The voltage difference between e and f is ____ V.

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TestHub · Accepted Answer

From symmetry, current through e-b and g-d $= 0$ .

Therefore, $R_{e q} = \frac{3}{4} \times R = \frac{3}{2} Ω$ .

Thus, current through battery $= \frac{6 \times 2}{3} = 4 A$ .

$i_{2} = \frac{4}{8} \times 2 = 1 A$

Therefore, $Δ V$ across e-f $= \frac{I _{2}}{2} \times R = \frac{1}{2} \times 2 = 1 V$ .

Physics - Current Electricity Question with Solution | TestHub

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