A meter bridge setup is shown in the figure. It is used to determine an unknown resistance $R$ using a given resistor of $15 Ω$ . The galvanometer $(G)$ shows null defection when tapping key is at $43 cm$ mark from end $A$ . If the end correction for end $A$ is $2 cm$ , then the determined value of $R$ will be $Ω$ .

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TestHub · Accepted Answer

Using the conditions of a balanced wheatstone bridge and adding the end correction. 15 R = l + e L + e - l + e ⇒ 15 43 + 2 = R 102 - 45 ⇒ R = 57 45 × 15 ⇒ R = 19 Ω

Physics - Current Electricity Question with Solution | TestHub

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