Physics - Current Electricity Question with Solution | TestHub

$\begin{array}{rl}& \frac{y-5}{2}+\frac{y-0}{2}+\frac{y-x+10}{1}=0\\ & y-5+y+2y-2x+20=0\\ & 4y-2x+15=0\dots .(\text{ (i) }\\ & \frac{x-5}{4}+\frac{x-0}{4}+\frac{x-10-y}{1}=0\\ & x-5+x+4x-40-4y=0\\ & 6x-4y-45=0..(i)\\ & \frac{-2x+4y+15=\mathrm{0..}(ii)}{4x-30=0}\\ & x=\frac{15}{2}\&4y-15+15=0\\ & y=0\\ & i=\frac{y-x+10}{1}\\ & i=\frac{0-7.5+10}{1}\\ & i=2.5A=\frac{n}{10}A\\ & n=25\end{array}$