Physics - Current Electricity Question with Solution | TestHub

Let the total current in the circuit be $I$.

The current passing through the galvanometer is $I_g=4\%\text{ of }I=\frac{4}{100}I=\frac{I}{25}$.

The galvanometer and the shunt resistance $S$ are connected in parallel, so the potential difference across them is equal.

$I_{g}G=(I-I_g)S$

Substituting $I_g=\frac{I}{25}$:

$\frac{I}{25}G=\left(I-\frac{I}{25}\right)S$

$\frac{I}{25}G=\frac{24I}{25}S$

$G=24S$

$S=\frac{G}{24}$

Answer: $\frac{\mathrm{G}}{24}$