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PhysicsCurrent ElectricityCircuit AnalysisEasy2 minPYQ_2020

PhysicsEasysingle choice

The value of the current $I_{1}, I_{2}$ and $I_{3}$ flowing through the circuit given below is

Options:

Answer:

Solution:

Applying Kirchoff's law

$10 - 6 I_{B} + 14 - 4 I_{A} = 0$ ...(loop 1)

$24 = 6 I_{B} + 4 I_{A}$

$12 = 3 I_{B} + 2 I_{A}$ .....(i)

$I_{A} = I_{B} + I_{C}$ .....(junction)

$10 - 6 I_{B} + 2 I_{C} = 0$ .....(loop 2)

$10 = 6 I_{B} - 2 I_{C}$

$10 = 6 I_{B} - 2 (I_{A} - I_{B})$ .....(ii)

On solving Equations (i) and (ii), we get

$I_{B} = 2 A, I_{A} = 3 A, I_{C} = 1 A$

Now as per given circuit,

$I_{1} = I_{B} = 2 A, I_{2} = - I_{A} = - 3 A$

$I_{3} = - I_{C} = - 1 A$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Circuit Analysis

⏱ 2mℹ️ Source: PYQ_2020

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