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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical PowerMedium2 minQB

PhysicsMediumnumerical

A resistor dissipates $192 J$ of energy in $1 s$ when a current of $4 A$ is passed through it. Now, when the current is doubled, the amount of thermal energy dissipated in $5 s$ is _____________ $J .$

Answer:

3840.00

Solution:

$P = i^{2} Rt$

$192 = 4 \times 4 \times R \times 1$

$R = 12Ω$

$P^{'} = (i^{'})^{2} Rt$ '

$= 8 \times 8 \times 12 \times 5 = 3840 J$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Electrical Power

⏱ 2mℹ️ Source: QB

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