The emf of a cell having internal resistance 1Ω is balanced against a length of 330 cm on a potentiometer wire. When an external resistance of 2Ω is connected across the cell, the balancing length wil

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The emf of a cell having internal resistance 1Ω is balanced against a length of 330 cm on a potentiometer wire. When an external resistance of 2Ω is connected across the cell, the balancing length will beNEET 2023 (Manipur)

TestHub · Accepted Answer

For case - I ​ ⇒ ε s ​ = ϕ × 330 ⇒ ϕ = 330 ε s ​ ​ ( cm V ​ ) … ​ For case - II ​ ⇒ i × 2 = ϕ I 2 ​ ⇒ 3 ε s ​ ​ × 2 = 330 ε s ​ ​ × I 2 ​ [From equation 1] ⇒ I 2 ​ = 220 cm ​

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