Physics - Current Electricity Question with Solution | TestHub

Here,

Length of the wire$=10\mathrm{m}$

Potential gradient of the wire,$\mathrm{k}=\text{0.8\hspace{0.17em}\hspace{0.17em}}\mathrm{V}{\mathrm{m}}^{-1}$

${\mathrm{l}}_2=2.45,{\mathrm{l}}_2=0.65$

$\Rightarrow \mathrm{\Delta l}={\mathrm{l}}_2-{\mathrm{l}}_1=1.8\text{m}$

$\mathrm{\Delta V}=\mathrm{k}·\left(\mathrm{\Delta l}\right)$

$=1.8\times 0.8$

$\therefore$The potential difference between$\mathrm{A}$and$\mathrm{B}$is

$\mathrm{\Delta V}={\mathrm{V}}_{\mathrm{B}}-{\mathrm{V}}_{\mathrm{A}}=1.96\mathrm{ V}-0.52\mathrm{ V}=1.44\mathrm{ V}$