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PhysicsCurrent ElectricityElectrical instrumentMedium2 minPYQ_2011

PhysicsMediumsingle choice

The rate of increase of thermo-emf with temperature at the neutral temperature of a thermocoupleNEET 2011 (Screening)

Answer:

Solution:

We have $e = a t + b t^{2}$ Natural temperature $\frac{d e}{d t} = a + 2 b t$ $T_{n} = - \frac{a}{2 b}$ At netural temperature $\frac{d e}{d t} = 0$

Stream:NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Electrical instrument

⏱ 2mℹ️ Source: PYQ_2011

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