Physics - Current Electricity Question with Solution | TestHub

Power =$100 \mathrm{W}$, Voltage =$200 \mathrm{V}$

The resistance of bulb =$\frac{{\mathit{\text{V}}}^2}{\mathit{\text{P}}}=\frac{200\times 200}{100}=400 \mathrm{\Omega }$

When the bulb is connected across$160 \mathrm{V}$,

Current in bulb =$\frac{160}{400} \text{A }$

Power consumption =$\mathit{\text{VI}}=160\times \frac{160}{400}$$= 64 \mathrm{W}$