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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityBatteryMedium2 minPYQ_2014

PhysicsMediumsingle choice

When a resistor of $11Ω$ is connected in series with a electric cell. The current following in it is $0.5 A$ . Instead when a resistor of $5Ω$ is connected to the same electric cell in series, the current increases by $0.4 A$ . The internal resistance of the cell is

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Solution:

$Here, i = \frac{E}{R + r} 0.5 = \frac{E}{11 + r} \Rightarrow E = 5.5 + 0.5 r 0.9 = \frac{E}{5 + r} or, E = 4.5 + 0.9 r$ On solving we get $r = 2.5Ω$

Stream:VITEEESubject:PhysicsTopic:Current ElectricitySubtopic:Battery

⏱ 2mℹ️ Source: PYQ_2014

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