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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical instrumentEasy2 minPYQ_2020

PhysicsEasysingle choice

Resistances of $100 Ω$ and $200 Ω$ are connected in series with $220 V$ mains. When a voltmeter of $1000 Ω$ resistance is connected in parallel to $100 Ω$ , then the reading of voltmeter is

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Answer:

Solution:

$R_{e q} = \frac{3200}{11} Ω$
$V = \frac{220}{(\frac{3200}{11})} \times \frac{1000}{11} = \frac{2200}{32} = 68.75 V$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Electrical instrument

⏱ 2mℹ️ Source: PYQ_2020

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