Physics - Current Electricity Question with Solution | TestHub

Current through$20\mathrm{ \Omega }=\mathrm{ }\frac{6}{20}$

current through$10\mathrm{ \Omega }=\mathrm{ }\frac{6}{10}$

Total current supplied by voltage source

$=\frac{6}{10}+\frac{6}{20}$

$=0.9\text{ A}$

Voltage of battery$=\mathrm{ }6\mathrm{ }+\mathrm{ }27\mathrm{ }=\mathrm{ }33\mathrm{ }\mathrm{v}\mathrm{o}\mathrm{l}\mathrm{t}$

Power supplied$=\frac{9}{10}\times \mathrm{ }33$

$=\mathrm{ }29.7\mathrm{ or}\mathrm{ }30 \mathrm{W}$( Approx )