Physics - Current Electricity Question with Solution | TestHub

Total potential difference$E_0$is given to both of the capacitor.
The two capacitors are then separately allowed to discharge through same resistors.
Since both capacitors are charged to same potential difference hence current at$t=0$,$I_0=\frac{E_0}{R}$will be same in both circuits.

Time taken in$50 \%$discharging$=\mathrm{R}\mathrm{C}\mathrm{l}\mathrm{n}\left(2\right)$

As$1^{st}$capacitance is 50% less than that of$2^{nd}$capacitance,

hence$1 \mu \mathrm{F}$will take less time compared to$2 \mu \mathrm{F}$