A charged particle having drift velocity of 7.5 × 10 − 4 m s − 1 in an electric field of 3 × 10 − 10 V m − 1 , has a mobility in m 2 V – 1 s – 1 of:NEET 2020 (Phase 1)

Drift velocity is given by, v d = E × μ ⇒ μ = v d E = 7 .5 × 10 − 4 3 × 10 − 10 μ = 2.5 × 10 6 m 2 V - 1 s - 1

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PhysicsCurrent ElectricityMicroscopicEasy2 minPYQ_2020

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A charged particle having drift velocity of $7.5 \times 10^{- 4} m s^{- 1}$ in an electric field of $3 \times 10^{- 10} V m^{- 1}$ , has a mobility in $m^{2} V^{- 1} s^{- 1}$ of:NEET 2020 (Phase 1)

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Solution:

Drift velocity is given by, $v_{d} = E \times μ$

$\Rightarrow μ = \frac{v_{d}}{E} = \frac{7 .5 \times 10^{- 4}}{3 \times 10^{- 10}}$

$μ = 2.5 \times 10^{6} m^{2} V^{- 1} s^{- 1}$

Stream:NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Microscopic

⏱ 2mℹ️ Source: PYQ_2020

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