Physics - Current Electricity Question with Solution | TestHub

In the above circuit the cells are connected with opposite polarity it means the net EMF is,$E=E_1+E_2=\left(2+4\right) \mathrm{V}=6 \mathrm{V}$and, all the resistance is connected in series,$R=R_1+R_2+R_3$$\Rightarrow I=\frac{2+4}{4+1+1}=\frac{6}{6}=1 \mathrm{A}$.