Physics - Current Electricity Question with Solution | TestHub

$\mathit{\text{P}}=\frac{{\mathit{\text{V}}}^2}{\mathit{\text{R}} }$so,$\mathit{\text{R}}=\frac{{\mathit{\text{V}}}^2}{\mathit{\text{P}}}$

$\therefore$${\mathit{\text{R}}}_1=\frac{{\mathit{\text{V}}}^2}{\text{100} }$and${\mathit{\text{R}}}_2={\mathit{\text{R}}}_3=\frac{{\mathit{\text{V}}}^2}{\text{60}}$

Now,${\mathit{\text{W}}}_1=\frac{{\left(\text{250}\right)}^2}{{\left({\mathit{\text{R}}}_1+{\mathit{\text{R}}}_2\right)}^2}·{\mathit{\text{R}}}_1$

${\mathit{\text{W}}}_2=\frac{{\left(\text{250}\right)}^2}{{\left({\mathit{\text{R}}}_1+{\mathit{\text{R}}}_2\right)}^2}·{\mathit{\text{R}}}_2$and${\mathit{\text{W}}}_3=\frac{{\left(\text{250}\right)}^2}{{\mathit{\text{R}}}_3}$

          W₁: W₂:W₃= 15 : 25 : 64

orW₁<W₂<W₃.