Physics - Current Electricity Question with Solution | TestHub

Resistance in the arms$\text{AC}$and$\text{BC}$are in series,



$\therefore {\text{R}}^{\prime }=3+3=6\mathrm{ \Omega }$

Now,$\text{R'}$and$\text{3}\text{Ω}$are in parallel,

$\therefore {\text{R}}_{\mathrm{e}\mathrm{q}}=\frac{6\times 3}{6+3}=2\mathrm{ \Omega }$

Now,$\text{V=IR}$

$⟹ \text{I}=\frac{3}{2}=\mathrm{1.5 }\mathrm{A}$