Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityCircuit AnalysisEasy2 minQB

PhysicsEasysingle choice

In the given circuit diagram, a wire is joining points B and D. The current in this wire is:

Answer:

Solution:

$R_{e ff} = \frac{4}{5} + \frac{6}{5} = 2Ω$

$i = \frac{20}{2}$

$= 10 A$

$I = \frac{4 i}{5} - \frac{3 i}{5} = + \frac{i}{5} = 2 A$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Circuit Analysis

⏱ 2mℹ️ Source: QB

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