Start Free Mock LoginAlready registered? Login here

Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical instrumentEasy2 minPYQ_2020

PhysicsEasysingle choice

The ratio of voltage sensitivity ( $V_{S}$ ) and current sensitivity ( $I_{s}$ ) of a moving coil galvanometer is

Options:

Answer:

Solution:

Voltage sensitivity $= \frac{Q}{V}$

Current sensitivity $= \frac{Q}{I}$

Also, potential difference

$V = I G$

Hence,

$∴ \frac{V_{s}}{I_{s}} = \frac{1}{G}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Electrical instrument

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...