Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical PowerHard2 minPYQ_2011

PhysicsHardsingle choice

If power dissipated in the $9Ω$ resistor in the circuit shown is $36 W$ , the potential difference across the $2Ω$ resistor is
NEET 2011 (Screening)

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Solution:

Electric power, $P = i^{2} R$ $∴$ Current, $i = \frac{P}{R}$ For resistance of $9Ω$ $i_{1} = \frac{36}{9} = 4 = 2 A$ $i_{2} i V_{2} = \frac{i _{1} \times R}{6} = \frac{2 \times 9}{6} = 3 A = i_{1} + i_{2} = 2 + 3 = 5 A = I R_{2} = 5 \times 2 = 10 V$

Stream:NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Electrical Power

⏱ 2mℹ️ Source: PYQ_2011

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