Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical instrumentEasy2 minPYQ_2020
PhysicsEasysingle choice

In the circuit figure, the voltmeter reads30 V. The resistance of the voltmeter is

Options:

Answer:
A
Solution:

The potential difference across300 Ω=60-30=30V
Therefore the effective resistance of voltmeter resistanceRand400 Ωin parallel will be equal to300 Ω, as 60 V is equally divided between two parts.
So,  300=R×400R+400

or300R +120000=400R or R=1200 Ω

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Electrical instrument
⏱ 2mℹ️ Source: PYQ_2020

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