Physics - Current Electricity Question with Solution | TestHub

Applying $KVL$ in loop $ABCDA,ABFEA,ABGHA$ and $ABIIA$, we get $$\begin{array}{rl}& 30-i_1\times 11=-25\\ & 20+i_2\times 5=25\\ & 5-i_3\times 10=-25\\ & 10+i_4\times 5=25\end{array}$$ Solving equations (i), (ii), (iii) and (iv) we get $i_1=5\mathrm{A},i_2=1\mathrm{A},i_3=3\mathrm{A}$ and $i_4=3\mathrm{A}$. Hence, current flowing through $25\mathrm{V}$ cell is $12\mathrm{A}$.