Physics - Current Electricity Question with Solution | TestHub

the equivalent resistance of the circuit

$\mathit{\text{R}}=\frac{3\times 12}{3+12}=\frac{36}{15}=\frac{12}{5}\mathrm{ \Omega }$

$\therefore$Current in circuit,$\mathit{\text{I}}=\frac{\mathit{\text{V}}}{\mathit{\text{R}}}$

$=\frac{4·8}{\left(\frac{12}{5}\right)}=\frac{4·8\times 5}{12}=2 \mathrm{A}$