Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionDynamicsMedium2 minQB

PhysicsMediuminteger

A simple pendulum consists of a bob of mass m and a string of length R suspended from a peg $P_{1}$ on the wall. A second peg $P_{2}$ is fixed vertically below the first one at a distance $3 R /7$ from it. The pendulum is drawn aside such that the string is horizontal and released. The maximum height (with respect to the lowest point) to which it rises is $\frac{α R}{28}$ . Find $α$ .

Answer:

Solution:

Initial KE at lowest point: $m g R$

New radius $R^{'} = \frac{4 R}{7}$

$m g R - m g \cdot \frac{R}{28} = m g \cdot \frac{27 R}{28}$

Given: $h = \frac{α R}{28}$

$m g \cdot \frac{27 R}{28} = m g \cdot \frac{α R}{28}$

$α = 27$

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Dynamics

⏱ 2mℹ️ Source: QB

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