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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle moves in a circle of radius $0.25 m$ at angular speed of two revolutions per second. The acceleration of the particle in $m s^{- 2}$ is

Options:

Answer:

Solution:

$r = 0.25 m$

$ω = 2 r e v . / s$

$ω = 2 \times 2 π r a d / s$

We know that $a_{c} = ω^{2} r$

$\Rightarrow$ $a_{c} = {(2 \times 2 π)}^{2} \times 0.25$

$a_{c} = 4 π^{2} m s^{- 2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Circular MotionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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