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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionDynamicsMedium2 minQB

PhysicsMediumsingle choice

A ring of mass $2 π kg$ and of radius 0.25 m is making 300 rpm about an axis through its perpendicular to its plane. The tension in newton developed in ring is approximately

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Answer:

Solution:

For a rotating ring, $2 T = \int_{0}^{π} \frac{m}{2 π} ω^{2} R sin θ d θ$
$= \frac{m ω ^{2} R}{π}$ , so $T = \frac{m ω ^{2} R}{2 π}$ .
With $m = 2 π kg, ω$
$= 300 rpm$
$= 10 π rad / s, R$
$= 0.25 m$ :
$T = \frac{2 π \times 100 π ^{2} \times 0.25}{2 π} = 25 π^{2} \approx 247 \approx 250 N .$

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Dynamics

⏱ 2mℹ️ Source: QB

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