A bob is whirled in a horizontal plane by means of a string with an initial speed of $ω$ rpm. The tension in the string is $T$ . If speed becomes $2 ω$ while keeping the same radius, the tension in the string becomes:NEET 2024
Options:
Answer:
A
Solution:

$T = m ℓ ω^{2}$
$T^{'} = m ℓ (2 ω)^{2} T^{'} = 4 T$

Question

A bob is whirled in a horizontal plane by means of a string with an initial speed of $ω$ rpm. The tension in the string is $T$ . If speed becomes $2 ω$ while keeping the same radius, the tension in the string becomes:NEET 2024

Options:

Answer:

A

Solution:

$T = m ℓ ω^{2}$
$T^{'} = m ℓ (2 ω)^{2} T^{'} = 4 T$

TestHub · Accepted Answer

T = m ℓ ω 2 ​ T ′ = m ℓ ( 2 ω ) 2 T ′ = 4 T ​

Physics - Circular Motion Question with Solution | TestHub

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