Physics - Circular Motion Question with Solution | TestHub

The force of tension in the string provides the required centripetal force to keep the stone in circular motion.

$\therefore \text{T}=\frac{{\text{mv}}^2}{\text{R}}=\frac{0\text{.}3\times {\left(6\right)}^2}{1\text{.}5}=7\text{.}2\text{ N}$